math 10th formula padhe yahan

Aapko iss post me batayenge aap math 10th formula padhe yahan o bhi bilkul muft me aapko jo bhi math 9th, 10th formula chahiye aapko yahan par milega aap chahe  ise dekh kar copy par likh sakte hai

1. (α+в)²= α²+2αв+в²

2. (α+в)²= (α-в)²+4αв

3. (α-в)²= α²-2αв+в²

4. (α-в)²= (α+в)²-4αв

5. α² + в²= (α+в)² - 2αв.

6. α² + в²= (α-в)² + 2αв.

7. α²-в² =(α + в)(α - в)

8. 2(α² + в²) = (α+ в)² + (α - в)²

9. 4αв = (α + в)² -(α-в)²

10. αв ={(α+в)/2}²-{(α-в)/2}²

11. (α + в + ¢)² = α² + в² + ¢² + 2(αв + в¢ + ¢α)

12. (α + в)³ = α³ + 3α²в + 3αв² + в³

13. (α + в)³ = α³ + в³ + 3αв(α + в)

14. (α-в)³=α³-3α²в+3αв²-в³

15. α³ + в³ = (α + в) (α² -αв + в²)

16. α³ + в³ = (α+ в)³ -3αв(α+ в)

17. α³ -в³ = (α -в) (α² + αв + в²)

18. α³ -в³ = (α-в)³ + 3αв(α-в)

ѕιη0° =0

ѕιη30° = 1/2

ѕιη45° = 1/√2

ѕιη60° = √3/2

ѕιη90° = 1

¢σѕ ιѕ σρρσѕιтє σƒ ѕιη

тαη0° = 0

тαη30° = 1/√3

тαη45° = 1

тαη60° = √3

тαη90° = ∞

¢σт ιѕ σρρσѕιтє σƒ тαη

ѕє¢0° = 1

ѕє¢30° = 2/√3

ѕє¢45° = √2

ѕє¢60° = 2

ѕє¢90° = ∞

¢σѕє¢ ιѕ σρρσѕιтє σƒ ѕє¢

2ѕιηα¢σѕв=ѕιη(α+в)+ѕιη(α-в)

2¢σѕαѕιηв=ѕιη(α+в)-ѕιη(α-в)

2¢σѕα¢σѕв=¢σѕ(α+в)+¢σѕ(α-в)

2ѕιηαѕιηв=¢σѕ(α-в)-¢σѕ(α+в)

ѕιη(α+в)=ѕιηα ¢σѕв+ ¢σѕα ѕιηв.

» ¢σѕ(α+в)=¢σѕα ¢σѕв - ѕιηα ѕιηв.

» ѕιη(α-в)=ѕιηα¢σѕв-¢σѕαѕιηв.

» ¢σѕ(α-в)=¢σѕα¢σѕв+ѕιηαѕιηв.

» тαη(α+в)= (тαηα + тαηв)/ (1−тαηαтαηв)

» тαη(α−в)= (тαηα − тαηв) / (1+ тαηαтαηв)

» ¢σт(α+в)= (¢σтα¢σтв −1) / (¢σтα + ¢σтв)

» ¢σт(α−в)= (¢σтα¢σтв + 1) / (¢σтв− ¢σтα)

» ѕιη(α+в)=ѕιηα ¢σѕв+ ¢σѕα ѕιηв.

» ¢σѕ(α+в)=¢σѕα ¢σѕв +ѕιηα ѕιηв.

» ѕιη(α-в)=ѕιηα¢σѕв-¢σѕαѕιηв.

» ¢σѕ(α-в)=¢σѕα¢σѕв+ѕιηαѕιηв.

» тαη(α+в)= (тαηα + тαηв)/ (1−тαηαтαηв)

» тαη(α−в)= (тαηα − тαηв) / (1+ тαηαтαηв)

» ¢σт(α+в)= (¢σтα¢σтв −1) / (¢σтα + ¢σтв)

» ¢σт(α−в)= (¢σтα¢σтв + 1) / (¢σтв− ¢σтα)

α/ѕιηα = в/ѕιηв = ¢/ѕιη¢ = 2я

» α = в ¢σѕ¢ + ¢ ¢σѕв

» в = α ¢σѕ¢ + ¢ ¢σѕα

» ¢ = α ¢σѕв + в ¢σѕα

» ¢σѕα = (в² + ¢²− α²) / 2в¢

» ¢σѕв = (¢² + α²− в²) / 2¢α

» ¢σѕ¢ = (α² + в²− ¢²) / 2¢α

» Δ = αв¢/4я

» ѕιηΘ = 0 тнєη,Θ = ηΠ

» ѕιηΘ = 1 тнєη,Θ = (4η + 1)Π/2

» ѕιηΘ =−1 тнєη,Θ = (4η− 1)Π/2

» ѕιηΘ = ѕιηα тнєη,Θ = ηΠ (−1)^ηα

1. ѕιη2α = 2ѕιηα¢σѕα

2. ¢σѕ2α = ¢σѕ²α − ѕιη²α

3. ¢σѕ2α = 2¢σѕ²α − 1

4. ¢σѕ2α = 1 − ѕιη²α

5. 2ѕιη²α = 1 − ¢σѕ2α

6. 1 + ѕιη2α = (ѕιηα + ¢σѕα)²

7. 1 − ѕιη2α = (ѕιηα − ¢σѕα)²

8. тαη2α = 2тαηα / (1 − тαη²α)

9. ѕιη2α = 2тαηα / (1 + тαη²α)

10. ¢σѕ2α = (1 − тαη²α) / (1 + тαη²α)

11. 4ѕιη³α = 3ѕιηα − ѕιη3α

12. 4¢σѕ³α = 3¢σѕα + ¢σѕ3α

» ѕιη²Θ+¢σѕ²Θ=1

» ѕє¢²Θ-тαη²Θ=1

» ¢σѕє¢²Θ-¢σт²Θ=1

» ѕιηΘ=1/¢σѕє¢Θ

» ¢σѕє¢Θ=1/ѕιηΘ

» ¢σѕΘ=1/ѕє¢Θ

» ѕє¢Θ=1/¢σѕΘ

» тαηΘ=1/¢σтΘ

» ¢σтΘ=1/тαηΘ

» тαηΘ=ѕιηΘ/¢σѕΘ

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Yahan par aapko 9th,10th,11th,12th, sab ka formulla milega aapko jo bhi chahiye aapko mil jayega aap padh sakte hai thanks aapko agar achha lage to apne dosto ko share jarur kare .